× Didn't find what you were looking for? Ask a question
Top Posters
Since Sunday
k
3
r
3
j
3
V
3
l
3
2
J
2
1
2
n
2
O
2
h
2
d
2
Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
New Topic  
firehawk347 firehawk347
wrote...
Posts: 66
Rep: 1 0
11 years ago
How many milliliters of an aqueous solution of 0.172 M iron(III) bromide is needed to obtain 16.6 grams of the salt ?
Read 555 times
1 Reply

Related Topics

Replies
wrote...
#1
11 years ago
1molar solution of FeBr3 = 295.557g/mole So, 0.172mola solution of FeBr3 contains 295.557 x 0.172 = 50.8358 g/1000mL. Therefore to get 16.60g of the salt one needs to have (16.60 x 1000)/50.858 =326.54mL.
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  917 People Browsing
 111 Signed Up Today
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 571
  
 109
  
 191
Your Opinion
Which 'study break' activity do you find most distracting?
Votes: 820
Previous poll results: Which country would you like to visit for its food?