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Home Q & A Board Biology-Related Homework Help Genetics and Developmental Biology
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juliasarands juliasarands
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11 years ago
Show a Punnet square of a cross between someone with this disorder and a
heterozygous individual. If not applicable, state why.
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wrote...
#1
11 years ago
it is J

with having J as the dominant trait for NOT having the disease
wrote...
#2
11 years ago
joubert is autosomal recessive so the punnet square: draw a box with four squares in it
two small j's on top of the box, a large J and a small j on the side- these j's signify one parent with two recessive genes and one with a recessive gene for joubert and one with a dominant gene for the wildtype (normal genotype). In the upper left box it's Jj, upper right it's Jj, and the bottom two are jj
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