Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
Home Q & A Board Science-Related Homework Help Physics
New Topic  
symbo symbo
wrote...
Go to Answer
Posts: 1970
Rep: 2 0
7 years ago
Suppose Mercury had 5-to-3 spin-orbit coupling and that its sidereal period remained 88 days, as now.  What would be the time from noon to noon on Mercury, in days?
   A)  88    B)  147    C)  264    D)  440
Textbook 
Discovering the Universe

Discovering the Universe


Edition: 7th
Authors:
Read 251 times
2 Replies
Replies
Answer verified by a subject expert
discovererdiscoverer
wrote...
#1
Top Poster
Posts: 1374
Rep: 30 0
7 years ago
Sign in or Sign up in seconds to unlock everything for free
More solutions for this book are available here
1

Related Topics

symbo Author
wrote...
#2
6 years ago
Very informative, I appreciate the extra effort
New Topic      
Quick Reply
Explore
Post your homework questions and get free online help from our incredible volunteers
  1306 People Browsing
Start New Topic Take the Tour CoursesNew Study Tools Topics Trending Browse by Textbook
Live Chat
Related Images
  
 181
  
 142
  
 151
Your Opinion
Which industry do you think artificial intelligence (AI) will impact the most?
Votes: 352
Previous poll results: What's your favorite funny biology word?