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Home Q & A Board Biology-Related Homework Help Genetics and Developmental Biology
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ilovehkhk ilovehkhk
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11 years ago
Male patterned baldness is caused by a recessive allele on the X chromosome. An autosomal disorder called Sickle cell anemia is caused by crescent-shaped red blood cells while normal blood cells are round. If a person is heterozygous for the disorder, they have some normal red blood cells and some crescent-shaped red blood cells. Suppose a bald male with sickle cell anemia has children with a female that is homozygous normal for both disorders. What are the percentages of the expected phenotypes of their children?

Which one is the recessive, the crescent-shaped red blood cells causing the disorder or the normal red blood cells?

your help was appreciated
mimi.
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IlovehimIlovehim
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11 years ago
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lenaelle Author
wrote...
#2
11 years ago
50% will be bald
50% will have sickle cell
25% will carry the bald allele
25% will carry the sickle cell allele
wrote...
#3
11 years ago
lol...Daniel S. right

50% chance that it'll be a girl who is heterozygous for both traits  (makes crescent shaped cells but is normal and carries the X chromosome with the recessive allele for male pattern baldness)

50% chance that it'll be a boy who is heterozygous for sickle cell anemia but does not carry the recessive allele for male pattern baldness...
wrote...
#4
11 years ago
recessive allele of baldness _ a
dominant allele of baldness _ A
crescent-shaped red blood cells in male are dominant, because he's heterozygous for the disorder _ B
normal red blood cells are recessive _ b
female is AAbb
AaBb + AAbb
AB        Ab
Ab        
aB
ab
AABb _ won't be patterned with baldness, but it will have crescent-shaped blood cells
AAbb _ won't be patterned with baldness and have normal blood cells
AaBb _ won't be bald by phenotype, but will have a recessive gene of baldness, and will have crescent-shaped blood cells
Aabb _ won't be bald by phenotype, but will have a recessive gene of baldness, and will have normal blood cells
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