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pkclary pkclary
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Posts: 579
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6 years ago
Imagine that you've added the same indicator used by Monod to E. coli colonies growing on a plate with glucose and no lactose. One colony is yellow and the remainders are white. This result suggests that cells of the yellow colony
A) have constitutively active lacZ and lacY genes.
B) cannot activate either the lacZ or lacY gene.
C) can activate the lacY gene but cannot active the lacZ gene.
D) cannot metabolize lactose.
E) cannot transport lactose into the cell.
Textbook 
Biological Science, Canadian Edition

Biological Science, Canadian Edition


Edition: 2nd
Authors:
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mastemamastema
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6 years ago
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pkclary Author
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6 years ago
This helped my grade so much Perfect
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Smart ... Thanks!
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2 hours ago
Brilliant
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