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10 years ago Edited: 10 years ago, masterphysics
Situation
According to safety standard for air bags, the maximum acceleration during a car crash should not exceed 60 g and should last for no more than 36 ms.

Questions
A. In such a case, what force does the air bag exert on a 81.0kg person? Start with a free-body diagram.

Express the force in part (A) in terms of the person's weight.

I am normally good at math, but physics I am not integrating easy what so ever.  I really want to understand and be efficient at diagrams.

So I am trying to draw.  I have an 81 kg person with the force of the airbag going in the negative x direction.  In the positive x i have 60g acceleration.  Do i take the 36ms times the 60 g to get velocity?  But F=MA.  So doing that gives me m/s and not m/s^2 which i need.  TIA

Post Merge: 10 years ago

Ok actually first part is easy.  I just multiply 9.81m/s^2 x 60 x 81kg and i get 4.76 x 10^4

But how do i approach the 2nd part of the question?
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wrote...
10 years ago
study study study!
wrote...
Valued Member
10 years ago
According to safety standard for air bags, the maximum acceleration

Maybe you should be doing the same then.

Use the equation: F= MA

Solve:

60g = (60)(9.81)= 588.6 N

Then, F=(588.6)(72)

F= 42379.2 N, but if you're using Mastering Physics, type it in as 4.23x10^4 N.
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