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!JRon@n !JRon@n
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Posts: 91
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10 years ago
x^2-1 is less than or equal to the absolute value of x + 1. so it basically looks like this:

x^2-1 (less than or equal to) lx+1l

i hate precalculus. i'm a sophomore for gods sake.
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wrote...
#1
10 years ago
I'm sorry if I don't see this, but where is the question?
wrote...
#2
Educator
10 years ago
Do you want us to graph this for you?
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#3
Staff Member
Educator
10 years ago
x^2-1 <= lx+1l

Move all variables and constants to one side:

x2 - 1 - x - 1 <= 0

x2 - x - 2 <= 0

I could be wrong Confounded Face
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