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dcfredr dcfredr
wrote...
Posts: 26
Rep: 1 0
10 years ago
Consider the cell described below at 255 K:

Pb | Pb2+ (1.27 M) || Fe3+ (2.29 M) | Fe

Given the standard reduction potentials (Pb2+ + 2e- ---> Pb is -0.13 and Fe3+ + 3e- ---> Fe  is -0.036), calculate the cell potential after the reaction has operated long enough for the [Fe3+] to have changed by 1.432 M


I have literally tried this problem for two hours now and I know what the correct answer is but I don't know how to get it. Can someone explain in detail how to get to the answer? I don't know what im doing wrong....
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tperkins9295tperkins9295
wrote...
Posts: 21
Rep: 0 0
10 years ago
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