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aznmistyblue aznmistyblue
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Question 1.

Which of the given monomers would produce the condensation polymer shown?

An illustration depicts a condensation polymer. The polymer has a 25 carbon chain. From right to left, the C 1, C 7, C 13, C 19, and C 25 each is double bonded to an oxygen atom. C 2, C 8, C 14, and C 20 each is replaced by an oxygen atom. C 1 and C 22 is also bonded to a wavy bond.

An illustration depicts four monomers.The first compound labeled as Roman numeral one has a SMILES string of C1CCOC(=O)C1. The second compound labeled as Roman numeral two has a SMILES string of C1CCC(=O)OCC1. The third compound labeled as Roman numeral three has a SMILES string of C1CC(=O)OC1. The fourth compound labeled as Roman numeral four has a SMILES string of CC(=O)CCCC(=O)O.


▸ I

▸ II

▸ III

▸ IV

▸ C and D

Question 2.

Nomex is a synthetic polymer with the structure shown. What is the structure(s) of the monomer(s) that would produce Nomex?

An illustration depicts the chemical structure of a synthetic polymer named Nomex.The Nomex has four six membered benzene rings. The C 5 of the first benzene ring is bonded to N H which is further single bonded to another element. A wavy line is present on this single bond. The C 3 of the first benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to C 6 of the second benzene ring. The C 2 of the second benzene ring is bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to N H. The N H is further single bonded to C 5 of the third benzene ring. The C 3 of the third benzene ring is bonded to N H which is further bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to C 6 of the fourth benzene ring. The C 2 of the fourth benzene ring is bonded to a carbon atom. This carbon atom is double bonded to an oxygen atom and single bonded to another element. The terminal carbon atoms are also bonded to a wavy bond.

An illustration depicts four monomers.The first compound labeled as Roman numeral one has a SMILES string of c1cc(cc(c1)N)N. The second compound labeled as Roman numeral two has a SMILES string of c1cc(cc(c1)C(=O)O)C(=O)O. The third compound labeled as Roman numeral has a molecular formula, N H 2 N H 2. The fourth compound labeled as Roman numeral four has a SMILES string of CC(=O)c1cccc(c1)C(=O)C.


▸ I and II

▸ I and III

▸ II and III

▸ II and IV

▸ I and IV
Textbook 
Organic Chemistry

Organic Chemistry


Edition: 4th
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