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Home Q & A Board Science-Related Homework Help Physics
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julie7 julie7
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11 years ago
I push sideways on a box that masses 10kg that has a µ of 0.21 with the surface it sits on. It just begins to move, but I keep pushing with the same force. 5 seconds later it is 1.88m away. What is µk?
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#1
11 years ago
static friction Fs = µFn = 0.21 * 10kg * 9.8m/s² = 20.58 N
This, then, is the applied force.

In order to have travelled 1.88m in 5 s from rest with uniform acceleration,
s = 1.88m = ½at² = ½ * a * (5s)²
a = 0.15 m/s²
This implies that the net force Fnet = ma = 10kg * 0.15m/s² = 1.5 N
Then the kinetic friction Fk = Fapp - Fnet = 20.58N - 1.5N = 19.08 N

kinetic µ = Fk / mg = 19.08N / 98N = 0.19 m/s²
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