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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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tole034 tole034
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11 years ago
A 500 mL sample of a 0.350 M solution is left open on a lab counter for twl weeks, after which the concentration of the solution is 0.955 M. What is the new volume of the solution?
.183 L is the correct answer
plz help
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#1
11 years ago
Here is one way to do it:

First, find the moles present in the original solution:

0.500L x 0.350mole/L = 0.175 mole

Now we will find the new volume for the solution that makes is so it is now 0.955M

We will let X = the volume of the evaporated solution:

0.175 mole/X liters = 0.955mole/L

0.175mole = X liters x 0.955mole/L

0.175 mole/0.955mole/L = X Liters

0.183 = X liters
wrote...
#2
11 years ago
0.500Lx (0.350 mol/1L) = 0.175mol We cancel out L and left with moles.
We take moles and molarity to find liters
0.175mol x(1L/o.955mol) =0.183L We cancel out moles to find liters.
If i am not wrong .183L is correct
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