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Home Q & A Board Science-Related Homework Help Chemistry (Moderator: Laser_3)
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Juelz_9214 Juelz_9214
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11 years ago
What is the empirical formula for perfluoropropane if the compound contains 81% fluorine and 19% carbon by mass?

I'm trying to review for an exam and I just cant seem to figure this one out, so if anyone knows how I can solve this, please help me out.  You dont need to give the answer, just the steps i need to take to come to the solution.
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#1
11 years ago
replace all the hydrogens in proprane with fluorine and it's called perfluoropropane

C3F8
MW = 3x12 + 8x19 = 188

%F = 8x19/188  x 100 = 80.85% = 81%
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#2
11 years ago
C3F8

because there are a total of 3 carbons and a total of 8 flourines. I hope this helps!
wrote...
#3
11 years ago
81/19 ~ 4.26
19/12 ~ 1.58

empirical formula (C1.5F4)
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