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Home Q & A Board Science-Related Homework Help Physics
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rjavier1 rjavier1
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11 years ago
How does that velocity compare with the escape velocity from the Sun?

Describe how your results help account for the fact that red giants have strong stellar winds.
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#1
11 years ago
Gravitational acceleration, a = GM / r^2.  where G is the gravitational constant; M is the mass, and r is the radius.

a is proportional to mass and is inversely proportional to the square of the radius.

The escape velocity is proportional to gravitational acceleration and to gravitational force.

The red giant has a mass of 1 mega-suns and a radius of 140 solar radii.

The red giant has a gravitational acceleration, from a point at its center, of 1 million times that of the sun (from the a reference point of the center of the sun).  The gravitational acceleration, and hence the escape velocity of the red giant, at it's surface is 1 / (140^2) that of the sun at an equivalent mass.

Therefore, the red giant has an escape velocity, v = 10^6 / 140^2 = 51.02 times that of the sun.
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Smitty4Smitty4
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11 years ago
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