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lele lele
wrote...
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11 years ago
How do i write this as an algebraic expression.
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wrote...
11 years ago
6x + 3
wrote...
11 years ago
6x+3
wrote...
11 years ago
6 times a number increased by 3.?
6(n) + 3
6n + 3
wrote...
11 years ago
(2x + 1)/ (1/3) or (x+3)/(1/6)

depending if X is meant increased by 3 or the whole thing.
wrote...
11 years ago
n is the number

therefore 6n+3
wrote...
11 years ago
let x be a number.
6x is six times a number.
6x+3 is six times a number increased by 3.
wrote...
11 years ago
6x+18

It's originally 6 times (a number
  • increased by 3) sooo...
6(x+3)

distribute the 6 to get 6x + 18

The question is poorly worded however and should be more clear on whether the number is increased BEFORE or AFTER multiplied, but usually one would expect that the word 'increased' means 'before' whereas something like 'plus' or 'added to' would be ambiguous.
wrote...
11 years ago
Let x be a number

6x + 3
wrote...
11 years ago
Hi,

Let's break down the given written [worded] expression by noticing that '6 times a number' is simply 6 multiplied by a variable, 'x'.  Therefore, we can say:

6x

Now, when we mention that something is increased by 3, that means that we add 3 to 6x to get:

6x + 3 <==== FINAL ANSWER

I hope that helps you out!  Please let me know if you have any other questions!
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