Top Posters
Since Sunday
5
a
5
k
5
c
5
B
5
l
5
C
4
s
4
a
4
t
4
i
4
r
4
New Topic  
irina irina
wrote...
Posts: 919
10 years ago
Write the algebraic expression using one variable for the following statement. Solve the equation and give all three answers.

Equation (1pt)

Solution (1pt)

The sum of the third and twice the first of three consecutive odd integers is 49. Find all three consecutive odd integers.

Im sorry to ask such a hard question, But i really dont know how to do this, I have read over the lesson, and if someone can explain if if/when they help me! It would be greatly appreciated!
Thanks all!
Read 329 times
4 Replies
Replies
wrote...
10 years ago
let x be the first integer
x+2 is the second
x+4 is the third"The sum of the third..."  x+4"... and twice the first..." 2*x or 2x"... is 49." = 49

x+4 + 2x = 49
3x + 4 = 49
3x = 45
x = 15

so the integers are 15, 17, and 19

Check:
19 + 2(15) = 19 + 30 = 49

Best of luck!
Answer accepted by topic starter
fifamofifamo
wrote...
10 years ago
Sign in or Sign up in seconds to unlock everything for free
1

Related Topics

wrote...
10 years ago
Let x be your first odd integer, then the second is x+2 and the third is x+4 since adding two to an odd integer gives you the next odd integer. Now the problem says: the sum of the third and twice the first, this is (x+4)+2x = 49 this is your equation, which you can simplify as: 3x+4=49 (note that x+2x=3x).
Now solve for x, first substract 4 on each side:
3x+4-4=49-4
3x=45, now divide both sides by 3:
3x/3 = 45/3
x=15, this is your first integer, then
x+2 = 17, your second integer
x+4 = 19, your third integer.
irina Author
wrote...
10 years ago
Thx all
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1399 People Browsing
Related Images
  
 134
  
 473
  
 317
Your Opinion
Which industry do you think artificial intelligence (AI) will impact the most?
Votes: 352