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wang wang
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6 years ago
which of the following statements about signal transduction is correct?
A:Receptor tyrosine kinases are usually activated by dimerization and cis-phosphorylation
B:The diversity of heterotrimetric G protein complexes is primarily conferred by various Gb and Gr subunits
C:Nuclear hormone receptors translocate into nucleus upon ligand binding-activation,and can directly bind DNA to regulate gene expression
D:PIP2 is catalyzed by phospholipase C to generate IP3 and triglycerides
E:binding of catalytic subunit of PKA by the regulatory subunit activates PKA enzymatic activity
(more than one answers)
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#1
Educator
6 years ago
Quote from: wang (6 years ago)
C:Nuclear hormone receptors translocate into nucleus upon ligand binding-activation,and can directly bind DNA to regulate gene expression
D:PIP2 is catalyzed by phospholipase C to generate IP3 and triglycerides
E:binding of catalytic subunit of PKA by the regulatory subunit activates PKA enzymatic activity

I'm certain about C, D, and E. Not B or A. Any thoughts?
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wang Authorwang
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#2
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6 years ago Edited: 6 years ago, wang
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wrote...
#3
Educator
6 years ago Edited: 6 years ago, bio_man
I've never heard of cis phosphorylation of tyrosine kinase, but I have heard of trans.

https://www.sciencedirect.com/science/article/pii/S2212137415200188 (it's mentioned here)

In terms of E, look at this illustration.  When cAMP is available, the subunit dissociates, causing it to become active

https://upload.wikimedia.org/wikipedia/commons/thumb/6/66/Proteinkinase_1.svg/2000px-Proteinkinase_1.svg.png

You're right about DAG, it shouldn't be triglyceride. Good eye!
wang Author
wrote...
#4
6 years ago
option E:it says binding of  regulatory subunit .
so it should inactivate PKA enzymatic activity.
wrote...
#5
Educator
6 years ago
http://maillardlab.org/wp-content/uploads/2016/07/PKA_NEW-1024x429.png

Are you suggesting it should be the opposite way around?
wang Author
wrote...
#6
6 years ago Edited: 6 years ago, wang
Dissociation not binding of regular subunit make the enzyme active.This just what I mean. Slight Smile
Post Merge: 6 years ago

Apparently,option E is wrong.
wrote...
#7
Educator
6 years ago
Quote from: wang (6 years ago)
Dissociation not binding of regular subunit make the enzyme active.This just what I mean. Slight Smile
Post Merge: 6 years ago

Apparently,option E is wrong.

That's correct. Thanks for updating

I'll review your next question
wang Author
wrote...
#8
6 years ago
 Slight Smile
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