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Home Q & A Board Science-Related Homework Help Mathematics
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rivetcolin rivetcolin
wrote...
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Posts: 87
Rep: 1 0
11 years ago
G(y) = (y-1)^5 / (y^2+2y)^6

I know you have to use the quotient rule and the chain rule, but, I keep on getting the wrong answer. I get lost while simplifying everything. All the help is greatly appreciated.
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3 Replies
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wrote...
#1
11 years ago
-(y-1)^4(7y^2-10y-12)
_________________
       y^7(y+2)^7
wrote...
#2
11 years ago
G'(y) = (5(y-1)^4(y^2+2y)^6-6(2y+2)(y^2+2y)^5)/(y^2+2y)^12
Answer accepted by topic starter
tony12tony12
wrote...
#3
Posts: 84
Rep: 0 0
11 years ago
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