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jules_1978 jules_1978
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Posts: 90
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11 years ago
An alkane reacts with a halogen to form a halocarbon. What is the role of the UV light in this reaction?

A. it provides energy for the reaction.
B. It catalyzes the reaction.
C. It is released by the reaction.
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wrote...
11 years ago
A
wrote...
11 years ago
I'd pick A, but the purpose of the UV is to allow the halogen to undergo free radical initiation.
Cl2--UV-->2Cl ?

And with methane the propogation goes like this
CH4+Cl ? ---> CH3 ? +HCl

And finally termination, with chloromethane as the product
CH3?+Cl? ---> CH3Cl

Hopefully you can see the '? ' that represents an unpaired electron, making that molecule a free radical Slight Smile
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