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Mathguy3000 Mathguy3000
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5 years ago
Log of base 2 (2x+4) - log of base 2 (x-1)= 3
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Educator
5 years ago
Done:

The two logs both have the same base, so you can apply the log rules:

\(\log _2\left(2x+4\right)-\log _2(x-1)=3\)

\(\log _2\left(\frac{2x+4}{x-1}\right)=3\)

\(\frac{2x+4}{x-1}=2^3\)

\(2x+4=8\left(x-1\right)\)

\(2x+4=8x-8\)

\(12=6x\)

\(2=x\)
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