Find the derivative using the product rule

1. a) y= (1 - 2x^3 + x^2)(1/x^3 + 1)
->> What I did so far, but got stuck as I had to distribute the terms involving negative exponents:
1) y= (1 - 2x^3 + x^2)(1/x^3 + 1)

2) = (1 - 2x^3 + x^2) ] u (x^-3 + 1) ] v       v^1 = -3x^-4   u^1 = -6x^2 + 2x

3) = (1 - 2x^3 + x^2)(-3x^-4) + (x^-3 + 1)(-6x^2 + 2x)


b) y = -x^2 (4x - 1)(x^3 + 2x + 3)
Would the answer to this be, y^1 = -24x^5 + 5x^4 - 32x^3 - 30x^2 + 6x?

c) Same thing as a).
y = (2x^2 - √x)^2
1) = (2x^2 - √x)(2x^2 - √x)

2) = (2x^2 - x^1/2)(2x^2 - x^1/2)

3) = (2x^2 - x^1/2) (4x - 1/2x^-1/2) + (2x^2 - x^1/2)( 4x - 1/2x^-1/2)           
    v^1 = 4x - 1/2x^-1/2    u^1 = 4x - 1/2x^-1/2

ALSO, I know one question per topic, sorry. I did it because they relate to the same problem that I'm having, but if you would like me to post each question separately, let me know. Thanks