Top Posters
Since Sunday
g
3
3
2
J
2
p
2
m
2
h
2
s
2
r
2
d
2
l
2
a
2
New Topic  
Gman01234 Gman01234
wrote...
Posts: 101
Rep: 0 0
2 years ago
Pure acetic acid (CH3COOH) is a liquid and is known as glacial acetic acid. Calculate the molarity of a solution prepared by dissolving 10.00 mL of glacial acetic acid at 25 °C in sufficient water to give 500.0 mL of solution. The density of glacial acetic acid at 25 °C is 1.05 g mL-1.

▸ 1.26 × 103  mol L-1

▸ 21.0 mol L-1

▸ 0.0210 mol L-1

▸ 0.350 mol L-1

▸ 3.50 × 10-4  mol L-1
Textbook 
General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications


Edition: 11th
Authors:
Read 85 times
1 Reply
Replies
Answer verified by a subject expert
jodie1jodie1
wrote...
Posts: 64
Rep: 0 0
2 years ago
Sign in or Sign up in seconds to unlock everything for free
More solutions for this book are available here
1

Related Topics

Gman01234 Author
wrote...

2 years ago
Smart ... Thanks!
wrote...

Yesterday
Correct Slight Smile TY
wrote...

2 hours ago
Good timing, thanks!
New Topic      
Explore
Post your homework questions and get free online help from our incredible volunteers
  1094 People Browsing
 117 Signed Up Today
Related Images
  
 14838
  
 1140
  
 157
Your Opinion
What's your favorite math subject?
Votes: 293