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riojamsushi riojamsushi
wrote...
11 years ago
Danielle declared that the graph of y=sqrt(x^2 + x 1) - abs(x) has the line y = 1 as a horizontal asymptote. Use the definition of a horizontal asymptote (as a limit) to determine whether Danielle is correct.

We didn't really go over this is class so I'm completely confused on what to do.
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wrote...
11 years ago
if you use wolfram alfa to solve the equation, it tells you that there are asymptotes at -1/2 and 1/2.  because the definition of a horizontal asymptote is: limit as x approaches infinity of f(x) = a  then just say daniel is incorrect because the definition says that there is a horizontal asymptote at 1/2 and -1/2 not 1.
as far as solving it algebraically i'm lost too.

(im in Ken K's class and ran into the same problem that you did)
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